WebQ. Prove that : tan8θ−tan 6θ−tan2θ=tan8θ. tan6θ.tan2θ. Q. If sin theta =12/13 find the value of sin2 theta-cos2 theta×1/tan2 theta. Q. If tan θ + cot θ = 2, find the value of tan 2 θ + cot 2 θ. WebNov 27, 2024 · Here , in tanθ + cotθ = 2 , cotθ can be written as 1/tanθ . → tanθ + cotθ = 2 → tanθ + 1/tanθ = 2 → tan²θ + 1/tanθ = 2 → tan²θ + 1 = 2tanθ → tan²θ + 1² - 2tanθ = 0 → ( tanθ - 1 )² = 0 → tanθ - 1 = 0 → tanθ = 1 Now finding tan¹⁰θ + cot¹⁰θ Substituting cot¹⁰θ = 1/tan¹⁰θ → tan¹⁰θ + 1/tan¹⁰θ Substituting tan θ = 1 → 1¹⁰ + 1/1¹⁰ → 1 + 1/1 → 1 + 1
Trigonometric Identities Solver - Symbolab
WebShow that cottheta - tantheta = 2cot 2theta . Question Show that cotθ−tanθ=2cot2θ . Easy Solution Verified by Toppr cotθ−tanθ= sinθcosθ− cosθsinθ = sinθcosθcos 2θ−sin 2θ= sin2θ2cos2θ=2cot2θ Was this answer helpful? 0 0 Similar questions Prove 1−tan 22θtan 2θtan 22θ+tan 2θ =tan3θtanθ. Medium View solution > Assertion WebFeb 11, 2016 · Goal rearranging, cot(θ 2) = x for θ. Since most calculators or other aids don't have a "cot" button or a cot−1 or arccot OR acot button 1 (different word for the inverse … gif button not showing in teams
cot \theta+\tan \theta=2 \operatorname{cosec} \theta \), then f ...
WebIf theta is an acute angle and tantheta + cottheta = 2 , then tan^7 theta + cot^7 theta = 2 . Question If θ is an acute angle and tanθ+cotθ=2, then tan 7θ+cot 7θ=2. A True B False Easy Solution Verified by Toppr Correct option is A) tanθ+cotθ=2 tanθ+ tanθ1 =2 tanθtan 2θ+1=2 tan 2θ−2tanθ+1=0 (tanθ−1) 2=0 tanθ=1 θ=45 0 Therefore, http://www.math.com/tables/trig/identities.htm WebMar 12, 2024 · Hint: Recall that $ \tan \theta =\dfrac{1}{\cot \theta } $ . Square both the sides of the given equation and use the expansion: $ {{(a\pm b)}^{2}}={{a}^{2}}+{{b}^{2 ... gif by frame to png