Tīmeklis$\begingroup$ is there not another relation 5 -> 2 -> 5 for R2 o R1 given R1 has (5,2) and R2 has (5,5) $\endgroup$ – Rag. Nov 13, 2024 at 14:32 $\begingroup$ @Rag Yes, you are correct. I will edit my answer. Thanks. $\endgroup$ – John Wayland Bales. Nov 14, 2024 at 4:46 Tīmeklis2024. gada 15. aug. · A portal for computer science studetns. It hosts well written, and well explained computer science and engineering articles, quizzes and practice/competitive programming/company interview Questions on subjects database management systems, operating systems, information retrieval, natural language …
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TīmeklisAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ... TīmeklisJoin. Combines attributes of two relations into one. R3 = join(R1,D1,R2,D2) Given a domain from each relation, join considers all possible pairs of tuples from the two relations, and if their values for the chosen domains are equal, it adds a tuple to the result containing all the attributes of both tuples (discarding the duplicate domain D2). cnn world headline news
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