Nettet∫ cos (mpix/L)cos (npix/L) dx = ∫ sin (mpix/L)sin (npix/L) dx = Ldelta_ {m n} where Ldelta_ {m n} is a function that is 1 if m=n and 0 otherwise. Reply 1 17 years ago A just calculate the integrals! Reply 2 17 years ago A I will try to make my answer even more helpful than kikzen's! Use 2cos (A)cos (B) = cos (A + B) + cos (A - B) NettetWolfram Alpha is a great tool for calculating antiderivatives and definite integrals, double and triple integrals, and improper integrals. The Wolfram Alpha Integral Calculator …
Integration $ \int x^2 \cos(nx) dx - Mathematics Stack Exchange
NettetDetailed step by step solution for integral of cos((npix)/L)sin((npix)/L) Solutions Graphing Practice; New Geometry; Calculators; Notebook . Groups Cheat Sheets. Sign in; … NettetThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading dr phone horloge
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Nettet25. aug. 2024 · You have parentheses around all of n π x so the cosine function is applied to n π x = n π 0 = 0. The correct value is c o s ( n π 0) l = c o s ( 0) l = 1 l. ( If the parentheses were around the entire n π x l then the value would be c o s ( n π 0 l) = c o s ( 0) = 1 .) Share Cite Follow answered Aug 25, 2024 at 16:18 user247327 18.3k 2 11 20 NettetAnswer to Solved integral_-L^L cos n pi x/L cos m pi x/L dx = {0 n m. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Nettet16. nov. 2024 · By keeping both forms of the integral around we were able to show that not only is {cos( nπx L)}∞ n = 0 mutually orthogonal on −L ≤ x ≤ L but it is also mutually orthogonal on 0 ≤ x ≤ L. The only difference is the value of the integral when n = m and we can get those values from the work above. Let’s take a look at another example. dr phone fix st albert