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If 7 sin2 + 3 cos2 4 then tan

Web10 aug. 2024 · 7sin2θ + 3cos2θ = 4 ⇒ 7sin2θ +3cos2θ = 4(sin2θ + cos2θ) ⇒ 7sin2θ +3cos2θ = 4sin2θ + 4cos2θ ⇒ 7sin2θ −4sin2θ = 4cos2θ − 3cos2θ ⇒ 3sin2θ = cos2θ ⇒ … Web[Ans. x = 100] x 6 loga x.log10 a.loga 5 log10 10 log100 x log 4 2 [ Sol. .a 3 9 5 log10 x 1 6 log10 x .log a 5 log10 x 1 2 2 .a 3 3 5 6 log10 x 1 log10 x log10 x 1 log x.5 3 3 3.3 10 5 3 6 log10 x 10 log10 x.5 3 5 3 log x 2 5 10 5 3 3 Hence log10 x 2 x = 100 ] CLASS : XI (J-Batch) TIME : 60 Min. DPP. NO.-17 Select the correct alternative : (Only one is correct) …

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Web18 mei 2024 · If tan θ = 3/4, then cos2 θ – sin2 θ = A. \(\frac{7}{25}\) B. 1 C. \(\frac{4}{25}\) D. \(\frac{1}{25}\) LIVE Course for free. Rated by 1 million+ students Get app now Login. Remember. Register; Test; JEE; NEET; Home; Q&A; Unanswered; Ask a Question; Learn; Ask a Question. If tan θ = 3/4, then cos^2 θ – sin^2 θ = A. 7/25 B ... WebIf cosθ + cos2θ = 1, then what is sin2θ + sin4θ equal to? Q7. If sin α = 3 4, then cos α is - Q8. If the length of a shadow cast by a pole is √3 times the length of the pole, then the angle of elevation of the sun is - Q9. A tower stands vertically on the ground. jesus longest recorded conversation https://xhotic.com

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Web18 jun. 2024 · If 7 sin2θ + 3 cos2θ = 4, find θ. class-10 1 Answer +1 vote answered Jun 18, 2024 by Maanas (25.9k points) selected Jun 22, 2024 by Hetshree Best answer We have, 7sin2θ + 3cos2θ = 4 ⇒ 7sin2θ+ 3 (1 − sin2θ) = 4 (∵cos2θ + sin2θ = 1) ⇒ 7 sin2θ + 3 − 3 sin2θ = 4 ⇒ 4 sin2θ = 4 − 3 = 1 ⇒ sin2θ = 1 4 1 4 ⇒ sinθ = ± 1 √4 1 4 = ± 1 2 1 2 Web9 jan. 2024 · 7sin²θ + 3cos²θ = 4 7sin²θ + ౩ (1-sin²θ) = 4 7sin²θ+3-3sin²θ = 4 4sin²θ+3 = 4 4sin²θ=1 sin²θ = 1/4 sinθ = +1/2 sinθ = + π/6 Therefore tan θ = + π/6 then we get tan θ = + 1/√3 Advertisement Still have questions? Find more answers Ask your question Web3 okt. 2024 · Class 7 Chapterwise MCQ Test. 0 votes. 1 answer. 7 sin2 θ + 3 cos2 θ = 4 7 sin 2 θ + 3 cos 2 θ = 4, then find tan θ tan θ. asked in Trigonometry by Lohith01 (97.1k … inspirations nursery

If tan θ = 3/4, then cos^2 θ – sin^2 θ = A. 7/25 B. 1 C. 4/25 D.

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If 7 sin2 + 3 cos2 4 then tan

If 7 sin^2θ + 3 cos^2θ = 4, find θ. - Sarthaks eConnect Largest ...

WebPh-1,2,3 & Seq & Prog13th - Free download as PDF File (.pdf), Text File (.txt) or read online for free. Question bank on Compound angles, Trigonometric eqn and ineqn, Solutions of … Web6. s secantAte the following:Find the exact value of (sec 30°) (cos 30º)-(tan 60°) (cot 60°)Evaluate:5 sin2 30°+ cos2 45°+4 ta72 6092 sin 30- COS 45°+tan 45º Answer: here is my answer I screen shot nalang made sabe ni brainly my answer is rude. 7. Activity 3: Find the exact values of the following. 1. cos 5850 seotud 2.

If 7 sin2 + 3 cos2 4 then tan

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Web4 3 4 6 6 Q.6 If f (x) = 3 sin x sin (3 x ) – 2 sin x sin (5 x ) then, for all permissible 2 2 values of x, f (x) is (A) – 1 (B) 0 (C) 1 (D) not a constant function Subjective : Q.7 If an equilateral triangle and a regular hexagon have the same perimeter then find the ratio of their areas. tan 3 cot 3 1 2 sin 2 cos 2 Q.8 Prove the identity, . 1 tan 2 1 cot 2 sin cos Web9 jan. 2024 · 7sin²θ + 3cos²θ = 4 7sin²θ + ౩ (1-sin²θ) = 4 7sin²θ+3-3sin²θ = 4 4sin²θ+3 = 4 4sin²θ=1 sin²θ = 1/4 sinθ = +1/2 sinθ = + π/6 Therefore tan θ = + π/6 then we get tan θ …

WebFree math problem solver answers your trigonometry homework questions with step-by-step explanations. Web10 dec. 2024 · If 7 sin 2 θ + 3 cos 2 θ = 4, 0° < θ < 90°, then the value of (tan 2 2θ + cosec 2 2θ) is: This question was previously asked in SSC CPO Previous Paper 29 (Held On: …

WebIf : `3 sin 2 theta = 5 + 4 cos 2 theta , "then": tan theta =` A)1 B)3 C)4 D)5 WebIf 7sin^2theta + 3cos^2theta = 4 then prove that sectheta + cosec theta = 2 + 2/√ (3) . Class 10. >> Maths. >> Introduction to Trigonometry. >> Trigonometric Identities. >> If …

Web29 mrt. 2024 · If 4 tan θ = 3, then ( (4 sin⁡ θ - cos⁡ θ)/ (4 sin⁡ θ + cos⁡ θ)) is equal to (A) 2/3 (B) 1/3 (C) 1/2 (C) 3/4 This video is only available for Teachoo black users Subscribe Now Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 …

WebIf tan theta = 3/4, find the value of 1-cos^2 theta / 1+cos^2 theta - YouTube If tanθ = 3/4 , find the value of (1 - cos² θ) / (1 + cos² θ)Trigonometry Class X Math Important... inspirations nortonWeb25 mrt. 2024 · Here is your answer !! 7 sin²A + 3 cos²A = 4 => 3 sin²A + 3 cos²A + 4 sin²A = 4 => 3 ( sin²A + cos²A ) + 4 sin²A = 4 => 3 + 4 sin²A = 4 => 4 sin²A = 1 => sin²A = 1/4 => sin A = 1/2 => sin A = sin 30° => A = 30° . So , tan A = tan 30° = 1/√3 ........... [Proved] Hope it helps !! plz follow if u lyk my answer Advertisement vinod04jangid Answer: jesus looked at the crowd with compassionWeb28 aug. 2024 · If 4tan theta = 3 then ( cos square theta - sin square theta) =? See answers Advertisement Advertisement MaheswariS MaheswariS If 6 tan A -5 = 0 find the value of( 3 Sin A - Cos A) / (5 Cos A + 9 sin A) brainly.in/question/5331430. If 1+tan theta=√2 then cot theta-1= ... inspirations no one can take your placeWebPh-1,2,3 and Seq. & Prog(13th) - Free download as PDF File (.pdf), Text File (.txt) or read online for free. Question bank on Compound angles, Trigonometric eqn and ineqn, Solutions of Triangle, Sequence & Progression There are 132 questions in this question bank. Select the correct alternative : (Only one is correct) Q.1 If x + y = 3 – cos4 and x – y = 4 sin2 … inspirations new yearWeb7 apr. 2024 · The tangents at P and Q intersect at a point T. Find the length TP. Topic: All topics. View solution. Question Text. 1) If 3cotA=4, check whether 1+tanA1−tanA. . … jesus looked towards heavenWeb7 sin 2 θ + 3 cos 2 θ = 4 ⇒ 7 sin 2 θ + 3 ( 1 − sin 2 θ) = 4 ⇒ 7 sin 2 θ + 3 − 3 sin 2 θ = 4 ⇒ 4 sin 2 θ = 1 ⇒ sin 2 θ = 1 4 ⇒ sin θ = 1 2 ⇒ sin θ = sin 30 ∘ ⇒ θ = 30 ∘ tan 30 ∘ = 1 3 A l t e r n a t e: Put θ = 30 ∘ 7 × sin 2 30 ∘ + 3 cos 2 30 ∘ = 4 ⇒ 7 × 1 4 + 3 × 3 4 = 4 ⇒ 7 4 + 9 4 = 4 ⇒ 16 4 = 4 ⇒ 4 = 4 ( Satisfied) ∴ tan 30 ∘ = 1 3 inspirations nursery horsforthWebIf tan θ = 3 4 then cos 2 θ − sin 2 θ = Options 7 25 1 − 7 25 4 25 Advertisement Remove all ads Solution Given that: θ tan θ = 3 4 Since Perpendicular Base tan x = Perpendicular Base ⇒ Perpendicular Perpendicular = 3 ⇒ Base Base = 4 ⇒ Hypotenuse Hypotenuse = s e r t ( 9 + 16) ⇒ Hypotenuse Hypotenuse = 5 jesus looking around corner